9x^2+34x+32=0

Solution for 9x^2+34x+32=0 equation:

9x^2+34x+32=0

a = 9; b = 34; c = +32;
Δ = b2-4ac
Δ = 342-4·9·32
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34)-2}{2*9}=\frac{-36}{18}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34)+2}{2*9}=\frac{-32}{18}
=-1+7/9
$